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42x^2+59x+8=0
a = 42; b = 59; c = +8;
Δ = b2-4ac
Δ = 592-4·42·8
Δ = 2137
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(59)-\sqrt{2137}}{2*42}=\frac{-59-\sqrt{2137}}{84} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(59)+\sqrt{2137}}{2*42}=\frac{-59+\sqrt{2137}}{84} $
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